SOLUTION: "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly

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Question 552827: "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly appreciated.
Found 2 solutions by AnlytcPhil, Edwin McCravy:
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
"The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly appreciated.
The Greek letter q is "theta", not "pheta". J

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The formula for q in radians, not degrees, is 

q = s%2Fr 

where s = the arc length and r = the radius.

So in radians

q = 20in%2F%289in%29 = 20%2F9(radians)

To convert radians to degrees, we multiply by %22180%B0%22%2Fpi

expr%2820%2F9%29expr%28%22180%B0%22%2Fpi%29 = 127.3239545°

To the nearest degree: 127°

Edwin





Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
You must not have gotten to radian measure.
See if this is the way you were taught.  It's the same answer.

s = pi%2F180·r·q

20 = pi%2F180·9·q
 
The 9 will divide into the 180 and give 20 on the bottom:

20 = pi%2F20·q
 
Now we multiply both sides by 20

400 = p·q

Now we divide both sides by p

400%2Fpi = q

127.3239545° = q

To the nearest degree is 127°.  Same as the other one I posted here.

Edwin