SOLUTION: "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly
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-> SOLUTION: "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly
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Question 552827: "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly appreciated. Found 2 solutions by AnlytcPhil, Edwin McCravy:Answer by AnlytcPhil(1806) (Show Source):
You can put this solution on YOUR website! "The central angle pheta of a circle with radius 9 inches intercepts an arc of 20 inches. Find pheta to the nearest degree." Thats the problem word for word, any help is strongly appreciated.
The Greek letter q is "theta", not "pheta". J
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The formula for q in radians, not degrees, is
q =
where s = the arc length and r = the radius.
So in radians
q = = (radians)
To convert radians to degrees, we multiply by = 127.3239545°
To the nearest degree: 127°
Edwin
You must not have gotten to radian measure.
See if this is the way you were taught. It's the same answer.
s = ·r·q
20 = ·9·q
The 9 will divide into the 180 and give 20 on the bottom:
20 = ·q
Now we multiply both sides by 20
400 = p·q
Now we divide both sides by p
= q
127.3239545° = q
To the nearest degree is 127°. Same as the other one I posted here.
Edwin