SOLUTION: How would I solve (b^4)^6*(b^2)^4 I know the answer is "b to the 32" I need to know how to get there.

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Question 552701: How would I solve (b^4)^6*(b^2)^4
I know the answer is "b to the 32" I need to know how to get there.

Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
How would I solve (b^4)^6*(b^2)^4
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You can't solve it, it's not an equation.
You can simplify it some.
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(b^4)^6 --> when raising to a power, multiply the exponents
%28b%5E4%29%5E6+=+b%5E%284%2A6%29+=+b%5E24
----
%28b%5E2%29%5E4+=+b%5E8
----
--> b%5E24%2Ab%5E8 when you multiply, add the exponents
--> b%5E32

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
%28b%5E4%29%5E6%2A%28b%5E2%29%5E4 First multiply the exponents inside the parentheses by the appropriate exponents on the outside.
%28b%5E4%29%5E6+=+b%5E24 and %28b%5E2%29%5E4+=+b%5E8 so now you have:
b%5E24%2Ab%5E8 Now you add the exponents since the base is the same (that's b) and you are multiplying the two factors.
b%5E%2824%2B8%29+=+b%5E32