Question 552701: How would I solve (b^4)^6*(b^2)^4
I know the answer is "b to the 32" I need to know how to get there. Found 2 solutions by Alan3354, Earlsdon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! How would I solve (b^4)^6*(b^2)^4
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You can't solve it, it's not an equation.
You can simplify it some.
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(b^4)^6 --> when raising to a power, multiply the exponents
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--> when you multiply, add the exponents
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You can put this solution on YOUR website! First multiply the exponents inside the parentheses by the appropriate exponents on the outside. and so now you have: Now you add the exponents since the base is the same (that's b) and you are multiplying the two factors.