SOLUTION: At your lemonade stand you charge .50 for a half cup and .75 for a full cup. At the end of the day, you see 12 cups were used and you made $8.00. How many of each size of drink did

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At your lemonade stand you charge .50 for a half cup and .75 for a full cup. At the end of the day, you see 12 cups were used and you made $8.00. How many of each size of drink did      Log On


   

Question 552670: At your lemonade stand you charge .50 for a half cup and .75 for a full cup. At the end of the day, you see 12 cups were used and you made $8.00. How many of each size of drink did you ssll
Found 2 solutions by fcabanski, josmiceli:
Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
Call half cups H and full cups F.


12 cups were used so H + F = 12


You sold $8 so .5H + .75F = 8


Solve the first equation in terms of one variable.
H+F=12
F = 12-H | Substitute that into the second equation.
.5H + .75(12-H) = 8
.5H + 9 - .75H = 8
-.25H = -1
H = 4


H+F = 12
4+F=12
F=12-4=8

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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let f = number of full cups sold
Let h = number of half cups sold
given:
(1) +h+%2B+f+=+12+
(2) .5h+%2B+.75f+=+8+
---------------
(2) +50h+%2B+75f+=+800+
Multiply both sides of (1) by +50+
and subtract (1) from (2)
(2) +50h+%2B+75f+=+800+
(1) +-50h+-+50f+=+-600+
+25f+=+200+
+f+=+8+
and, since
(1) +h+%2B+8+=+12+
(1) +h+=+4+
You sold 4 half cups and 8 full cups