SOLUTION: at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the jogge
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Question 552481: at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the joggers meet? Found 2 solutions by mananth, josmiceli:Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! distance = 8 miles
the runners are in opposite directions
so add up speeds
6+4 = 10 mph
t=d/r
8/10 = 4/5 of an hour
4/5 *60 = 48 minutes
They will meet at 7:48 AM
You can put this solution on YOUR website! Let = time in hrs it takes to meet
Let = distance faster runner goes in hrs
given:
Faster runner:
Slower runner:
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By substitution: hrs hrs = 7:48 AM
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check answer: mi
and mi
OK
