SOLUTION: Find four consecutive odd integers such that the sum of the second and the fourth is 63 more than one-fifth of the third. Please show your solution.... i need this.........and the

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Question 55235: Find four consecutive odd integers such that the sum of the second and the fourth is 63 more than one-fifth of the third. Please show your solution.... i need this.........and the equation
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Find four consecutive odd integers such that the sum of the second and the fourth is 63 more than one-fifth of the third.
When you count by odds you are adding 2.
Let the 1st integer=x
Then the 2nd integer=x+2
Then the 3rd integer=x+2+2=x+4
Finally, the fourth=x+2+2+2=x+6
Sum means add and is means = and one-fifth means 1/5*whatever and more means add:
%28x%2B2%29%2B%28x%2B6%29=%281%2F5%29%28x%2B4%29%2B63
2x%2B8=x%2F5%2B4%2F5%2B63 Make your life easier by clearing the fractions, multiply everything by 5.
5%282x%29%2B5%288%29=5%28x%2F5%29%2B5%284%2F5%29%2B5%2863%29
10x%2B40=x%2B4%2B315
10x%2B40=x%2B319
-x%2B10x%2B40=-x%2Bx%2B319
9x%2B40=319
9x%2B40-40=319-40
9x=279
9x%2F9=279%2F9
x=31
The 1st integer:x=31
The 2nd integer:x+2=31+2=33
The 3rd integer:x+4=31+4=35
The fourth integer:x+6=31+6=37
Happy Calculating!!!