Question 552021: OK this might be hard to read but its a proof-
so PA(line segment) is congruent to PB and QA is congruent to QB is given
PQ is congruent to PQ (reflexive)
Then triangle PAQ is congruent to PBQ is it because of symmetric property?
Then angle APQ is congruent to BPQ is that corresponding angles?
PR is congruent to PR because of reflexive
Triangle APR is congruent to BPR is that corresponding angles also?
Answer by neatmath(302)   (Show Source):
You can put this solution on YOUR website!
Without a sketch, this is what I am seeing:
1. PA=PB given
2. QA=QB given
3. PQ=PQ reflexive property
4. triangle PAQ = triangle PBQ Side-Side-Side Theorem (SSS)
5. angle APQ = angle BPQ Corresponding parts of congruent triangles are congruent (CPCTC)
6. PR=PR reflexive property
7. triangle APR = triangle BPR Side-Angle-Side Theroem (SAS)
For the final step, we used steps 1, 5, and 6 in order to use the SAS Theorem.
and of course all the equal signs (=) above should be congruency signs.
This is what I'm seeing without looking at your sketch.
You were close on some of the things, but don't forget to use your CPCTC, SAS, SSS, AAS, and ASA Theorems properly!
Also, number your proof steps as I did above, and it will make it easier to read, and easier to get help with.
I hope this helps! :)
Email Scott: neatmath@yahoo.com for help with specific problems,
or to inquire about mathematics tutoring via email or other methods.
Paypal is always accepted for single problems or for more intensive tutoring!
Single problems would range from 50 cents to 5 dollars each, depending on the complexity.
|
|
|
