SOLUTION: Can you please help me? This problem isn't in the book. 3(y-2)+y(1+2)=4 3y-6+1y+2y=4 then what? 6y-6=4-6???? what's after that???

Algebra ->  Expressions-with-variables -> SOLUTION: Can you please help me? This problem isn't in the book. 3(y-2)+y(1+2)=4 3y-6+1y+2y=4 then what? 6y-6=4-6???? what's after that???      Log On


   

Question 55197This question is from textbook
: Can you please help me? This problem isn't in the book.
3(y-2)+y(1+2)=4
3y-6+1y+2y=4
then what?
6y-6=4-6???? what's after that??? This question is from textbook

Found 3 solutions by venugopalramana, Earlsdon, anjulasahay:
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
SEE THE FOLLOWING EXAMPLE AND TRY...IF STILL IN DIFFICULTY PLEASE COME BACK.
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I really don't understand this problem. Can you please help me?
3(1-3x)+2=4x+14........OK
3-9x+2=4x+14................GOOD
so then add or subtract from both sides?
3-9x+9x+2=13+14......HERE YOU GOT CONFUSED..THE STEPS INVOLVED ARE
1.REMOVE BRACKETS ......THIS YOU HAVE DONE.
2.TRANSFER ALL UNKNOWN TERMS TO ONE SIDE.... USUALLY L.H.S. AND KNOWN TERMS TO ONE SIDE ...USUALLY R.H.S.
3.THIS TRANSFER YOU CAN THINK OF AND DO AS FOLLOWS....
EVERY TERM HAS A + OR - SIGN INFRONT OF IT.WHEN YOU TRANSFER THAT TERM FROM ONE SIDE TO ANOTHER ,+ BECOMES - AND - BECOMES PLUS.
THIS IS BECAUSE...AS YOU WERE TRYING TO SAY 'ADD OR SUBTRACT FROM BOTH SIDES'
AN EQUATION IS UNALTERED IF WE ADD OR SUBTRACT SAME QUANTITY FROM BOTH SIDES OF THE EQN.SO IF WE WANT TO REMOVE +4X ABOVE FROM R.H.S.WE HAVE TO ADD -4X TO IT.SO TO BALANCE IT AND KEEP THE VALIDITY OF THE EQN.UNALTERED,WE ADD -4X TO L.H.S.ALSO.THEN ON R.H.S ,WE GET +4X-4X=0...THAT IS +4X DIAPPEARS AS WE WANTED.BUT -4X REMAINS ON L.H.S.....THIS IS THE FINAL EFFECT OF ADD AND SUBTRACT WHICH IS SUMMARISED FIRST ABOVE.
HENCE WE GET HERE
-9X-4X = 14-2-3
4.NOW SIMPLIFY BOTH SIDES COMBINING ALL UNKNOWNS ON L.H.S AND ALL KNOWNS ON R.H.S
WE GET HERE
-13X=9
5.NOW TRANSFER THE COEFFICIENT OF UNKNOWN ON L.H.S.TO R.H.S.
APPLYING THE SAME RULE & LOGIC MENTIONED ABOVE,HERE * WILL BECOME / AND / BECOMES *
HERE WE GET
X = -9/13....
THIS IS THE ANSWER.
6.IF YOU HAVE TIME AND WOULD LIKE TO DO....CHECK BACK THE ANSWER FOR CONFIRMATION BY SUBSTITUTION..
3{1-3*(-9/13)}+2=4*(-9/13)+ 14
3{1+27/13)+2=-36/13 +14
3*40/13 +2=(-36+14*13)/13
120/13 +2= 146/13
146/13 = 146/13.......OK


Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for y:
3%28y-2%29%2By%281%2B2%29+=+4 Applying the distributive property to the left side.
3y-6%2By%2B2y+=+4 Collecting like-terms.
6y-6+=+4 Now add 6 to both sides of the equation.
6y+=+10 Finally, divide both sides by 6.
y+=+10%2F6 or y+=+5%2F3
y+=+1.66 Approximately.

Answer by anjulasahay(30) About Me  (Show Source):
You can put this solution on YOUR website!
Can you please help me? This problem isn't in the book.
3(y-2)+y(1+2)=4
3y-6+1y+2y=4
then what?
6y-6=4-6???? what's after that???
ans:
3(y-2)+y(1+2) = 4
or 3y-6+y(3)= 4
or 6y-6 = 4
or 6y = 4 + 6 = 10
or y = 10/6 = 5/3
note :
6y-6=4-6???? --- how u arrived at this because 4-6 is not valid .
you will move -6 from left to right side where it will have + sign
or you can understand like this
since both sides are equal you can add same number in both sides without affecting the values i.e.
6y-6=4
or 6y-6+6=4+6
or 6y = 4+6
or y = 10/6 = 5/3