SOLUTION: use the echelon method to solve: x+y=16 6x-y=33 cant seem to get it right

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Question 551877: use the echelon method to solve:
x+y=16
6x-y=33
cant seem to get it right

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I have not heard of an echelon method, but I have heard translations of the word echelon from the French into other languages to refer to a strategy to solve systems of linear equations.
You want to keep an equation involving both variables and replace the other equation with a combination of the two where one of the variables has been eliminated.
I would keep x%2By=16 because it's nice and simple and replace the other equation, using the sum of the two
x%2By%2B6x-y=16%2B33 --> 7x=49
The system is now
x%2By=16
7x=49
Even better, we can further simplify, dividing both sides by 7.
7x=49 --> x=7
So we could say that we now have the system
x%2By=16
x=7
Then substituting we get 7%2By=16 --> y=16-7=9
Maybe you were trying to eliminate instead of y to give your modified system the same shape as the one in the book.
We can do that too, if you get points for eliminating variables in alphabetical order.
Just multiply x%2By=16 times -6 to get -6x-6y=-96 and add it to
6x-y=33 to get
-6x-6y%2B6x-y=-96%2B33 --> -7y=-63
Then you could simplify it by dividing both sides by -7 to get
y=9