Question 55184: write an equation in slope-intercept form for the line that satisfies each set of conditions.
passes through (6,1),parallel to the line with X-intercept -3 and y-intercept 5
Answer by mathchemprofessor(65)  (Show Source):
You can put this solution on YOUR website! When a line have x-intercept -3 and y-intercept 5, the line passes through the points (-3,0) and (0,5).
So, the slope of the line,m= (5-0)/((0-(-3))=5/3,
using the formula m=(y2-y1)/(x2-x1).
When the other line is parallel to the above line, slope is the same.
So,m=5/3
The equation of the second line is y=(5/3)x+b
When it passes through the point (6,1),
1=(5/3)*6+b
1=10+b
b=-9
The required equation of the line is
y=(5/3)x-9
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