SOLUTION: The product of two consecutive odd integers is 195. i tried x(x+2)=195

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Question 5517: The product of two consecutive odd integers is 195.
i tried x(x+2)=195
Found 2 solutions by rapaljer, ichudov:
Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website!
You are right.
x(x+2) = 195

It's quadratic, and it factors.

Basically you need two numbers whose product is 195 and whose difference is only 2, so the numbers will be numerically very close together. Try a number that is near the square root of 195. It would be somewhere between 13 and 15. In fact that is IT: 13 and 15!!
(x+15)(x-13)= 0
There are two solutions:
In the first case:
x= -15
x+2= -13

In the second case:
x= 13
x+2 = 15.

R^2 at SCC

Answer by ichudov(507) (Show Source):
You can put this solution on YOUR website!
you are on the righ track. You need to solve x(x+2)=195, or

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=784 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 13, -15. Here's your graph:

the solutions are 13, -15, or two consecutive pairs:
-15,-13
13,15