SOLUTION: The length of a certain rectangle is 4cm greater than the side of a square. The width of the rectangle is 2cm less than the side of the square. The area of the rectangle is 6square
Algebra ->
Length-and-distance
-> SOLUTION: The length of a certain rectangle is 4cm greater than the side of a square. The width of the rectangle is 2cm less than the side of the square. The area of the rectangle is 6square
Log On
Question 551653: The length of a certain rectangle is 4cm greater than the side of a square. The width of the rectangle is 2cm less than the side of the square. The area of the rectangle is 6square cm greater than the area of the square. How long is each side of the square? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! side of square = x
Area of square = x^2
width of rectangle = x-2
length of rectangle = x+4
Area of rectangle = (x-2)(x+4)
=x^2+2x-8
x^2+2x-8=x^2+6
2x-8=6
2x=8+6
2x=14
/2
x=7
square side = 7 cm
