Question 55158: Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil?
Found 3 solutions by checkley71, Hook, funmath:
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! DISTANCE=RATE TIMES TIME
380=50T+60T
380=110T
T=380/110
T=3 5/11 HOURS LATER THEY MEET
PROOF
380=50(3 5/11)+60(3 5/11)
380=50*38/11+60*38/11
380=1900/11+2280/11
380=4180/11
380=380
Answer by Hook(36) (Show Source):
Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website! Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil?
The formula for distance is  , where d=distance, r=rate (or speed) and t=time
Ching's rate=50 mi/h
Ching's time=t
Ching's distance=50t
Phil's rate=60 mi/h
Phil's time=t-1 (Because he left an hour later, he drove an hour less.)
Phil's distance=60(t-1)
The total distance traveled=380 mi
Problem to solve for t:
50t+60(t-1)=380
50t+60t-60=380
(50+60)t-60=380
110t-60=380
110t-60+60=380+60
110t=440
110t/110=440/110
t=4
Ching will have to travel t=4 hrs.
(they didn't ask, but Phil would travelt-1=4-1=3hrs.)
Happy Calculating!!!
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