SOLUTION: In the remuda, the ratio of piebalds to mottled mares was 7 to 11. If there were 756 remounts in the remuda, how many were piebalds? Can you help me solve this. Thanks much!

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In the remuda, the ratio of piebalds to mottled mares was 7 to 11. If there were 756 remounts in the remuda, how many were piebalds? Can you help me solve this. Thanks much!      Log On


   



Question 551559: In the remuda, the ratio of piebalds to mottled mares was 7 to 11. If there were 756 remounts in the remuda, how many were piebalds? Can you help me solve this.
Thanks much!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
In the remuda, the ratio of piebalds to mottled mares was 7 to 11.
If there were 756 remounts in the remuda, how many were piebalds?
:
Let x = the multiplier
then
7x = no. of pies
and
11x = no. mots
:
A simple equation to find x
7x + 11x = 756
18x = 756
x = 756%2F18
x = 42 is the multiplier
therefore
7*42 = 294 pies
11*42 = 462 mots
;
:
Confirm this by finding the total: 294 + 462 = 756