SOLUTION: Completely factor the expression 147x^2y + 42xy^2 + 3y^3
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Question 551516
:
Completely factor the expression
147x^2y + 42xy^2 + 3y^3
Found 2 solutions by
scott8148, Earlsdon
:
Answer by
scott8148(6628)
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3y(49x^2 + 14xy + y^2)
3y(7x + y)(7x + y)
Answer by
Earlsdon(6294)
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Factor completely:
Each of the coefficients is divisible by 3y so factor a 3y.
The trinomial looks like a perfect square so...
Check by multiplying the factors.