SOLUTION: Megan factored the expression 28x^2 + x - 15 as (4x-3)(7x+5). But when Jacob applied the FOIL principle and multiplied out (4x-3)(7x+5), he got 28x^2 - x - 15; thus, Megan’s solut

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Megan factored the expression 28x^2 + x - 15 as (4x-3)(7x+5). But when Jacob applied the FOIL principle and multiplied out (4x-3)(7x+5), he got 28x^2 - x - 15; thus, Megan’s solut      Log On


   



Question 551510: Megan factored the expression 28x^2 + x - 15 as (4x-3)(7x+5). But when Jacob applied the FOIL principle and multiplied out (4x-3)(7x+5), he got 28x^2 - x - 15; thus, Megan’s solution does not appear to check. Why is that? Please help Megan to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 28x%5E2%2Bx-15, we can see that the first coefficient is 28, the second coefficient is 1, and the last term is -15.


Now multiply the first coefficient 28 by the last term -15 to get %2828%29%28-15%29=-420.


Now the question is: what two whole numbers multiply to -420 (the previous product) and add to the second coefficient 1?


To find these two numbers, we need to list all of the factors of -420 (the previous product).


Factors of -420:
1,2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210,420
-1,-2,-3,-4,-5,-6,-7,-10,-12,-14,-15,-20,-21,-28,-30,-35,-42,-60,-70,-84,-105,-140,-210,-420


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -420.
1*(-420) = -420
2*(-210) = -420
3*(-140) = -420
4*(-105) = -420
5*(-84) = -420
6*(-70) = -420
7*(-60) = -420
10*(-42) = -420
12*(-35) = -420
14*(-30) = -420
15*(-28) = -420
20*(-21) = -420
(-1)*(420) = -420
(-2)*(210) = -420
(-3)*(140) = -420
(-4)*(105) = -420
(-5)*(84) = -420
(-6)*(70) = -420
(-7)*(60) = -420
(-10)*(42) = -420
(-12)*(35) = -420
(-14)*(30) = -420
(-15)*(28) = -420
(-20)*(21) = -420

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 1:


First NumberSecond NumberSum
1-4201+(-420)=-419
2-2102+(-210)=-208
3-1403+(-140)=-137
4-1054+(-105)=-101
5-845+(-84)=-79
6-706+(-70)=-64
7-607+(-60)=-53
10-4210+(-42)=-32
12-3512+(-35)=-23
14-3014+(-30)=-16
15-2815+(-28)=-13
20-2120+(-21)=-1
-1420-1+420=419
-2210-2+210=208
-3140-3+140=137
-4105-4+105=101
-584-5+84=79
-670-6+70=64
-760-7+60=53
-1042-10+42=32
-1235-12+35=23
-1430-14+30=16
-1528-15+28=13
-2021-20+21=1



From the table, we can see that the two numbers -20 and 21 add to 1 (the middle coefficient).


So the two numbers -20 and 21 both multiply to -420 and add to 1


Now replace the middle term 1x with -20x%2B21x. Remember, -20 and 21 add to 1. So this shows us that -20x%2B21x=1x.


28x%5E2%2Bhighlight%28-20x%2B21x%29-15 Replace the second term 1x with -20x%2B21x.


%2828x%5E2-20x%29%2B%2821x-15%29 Group the terms into two pairs.


4x%287x-5%29%2B%2821x-15%29 Factor out the GCF 4x from the first group.


4x%287x-5%29%2B3%287x-5%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%284x%2B3%29%287x-5%29 Combine like terms. Or factor out the common term 7x-5


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Answer:


So 28x%5E2%2Bx-15 factors to %284x%2B3%29%287x-5%29.


In other words, 28x%5E2%2Bx-15=%284x%2B3%29%287x-5%29.


Note: you can check the answer by expanding %284x%2B3%29%287x-5%29 to get 28x%5E2%2Bx-15 or by graphing the original expression and the answer (the two graphs should be identical).