SOLUTION: ~Working together a man and woman can do the job in 8 hours. if either had to do it alone, it would take a woman 2 hours longer than a man. How long would it take either person wor

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: ~Working together a man and woman can do the job in 8 hours. if either had to do it alone, it would take a woman 2 hours longer than a man. How long would it take either person wor      Log On


   



Question 551349: ~Working together a man and woman can do the job in 8 hours. if either had to do it alone, it would take a woman 2 hours longer than a man. How long would it take either person working alone?
~A reservoir can be filled by one pipe in 6 hours and by another in 8 hours. It can be emptied by a third pipe in 10 hours. Starting empty, how long will it take to fill the reservoir if all pipes are open?

Found 2 solutions by mananth, richwmiller:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let Man take x hours to complete the job alone
so he does 1/x of the job in 1 hour
woman takes 1/(x+2) hours to do the same job
so she does 1/(x+2) of the job in 1 hour
Together they can do 1/x + 1/(x+2) of the job in 1 hour
add up both
=(2x+2)/x(x+2)
so they take x(x+2)/(2x+2) hours
x(x+2)/(2x+2)= 10
x(x+2)=10(2x+2)
x^2+2x=20x+20
x^2-18x-20=0
x^2-20x+2x-20=0
x(x-20)+2(x-20)=0
(x-20)(x+2)=0
Take the positive value
x= 20
Man takes 20 hours
Woman takes 20 +2 = 22 hours
------------
1/6 +1/8 - 1/10 is the job done in 1 hour ( filling the pool)
7/24 - 1/10
Addup
(70-24)/240
46/240 of the job is done in 1 hour
so it will take 240/46 hours = 5.2 hours
HAPPY NEW YEAR



Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
1%2Fx+%2B+1%2F%28x%2B2%29+=+1%2F8
Multiply by 8x(x+2) to remove denominators
8(x+2) + 8x = x(x+2)
x^2 -14x - 16 = 0
(Reject the negative solution for time)
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-14x%2B-16+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-14%29%5E2-4%2A1%2A-16=260.

Discriminant d=260 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--14%2B-sqrt%28+260+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-14%29%2Bsqrt%28+260+%29%29%2F2%5C1+=+15.0622577482985
x%5B2%5D+=+%28-%28-14%29-sqrt%28+260+%29%29%2F2%5C1+=+-1.06225774829855

Quadratic expression 1x%5E2%2B-14x%2B-16 can be factored:
1x%5E2%2B-14x%2B-16+=+1%28x-15.0622577482985%29%2A%28x--1.06225774829855%29
Again, the answer is: 15.0622577482985, -1.06225774829855. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-14%2Ax%2B-16+%29

Solved by pluggable solver: COMPLETING THE SQUARE solver for quadratics
Read this lesson on completing the square by prince_abubu, if you do not know how to complete the square.
Let's convert 1x%5E2%2B-14x%2B-16=0 to standard form by dividing both sides by 1:
We have: 1x%5E2%2B-14x%2B-16=0. What we want to do now is to change this equation to a complete square %28x%2Bsomenumber%29%5E2+%2B+othernumber. How can we find out values of somenumber and othernumber that would make it work?
Look at %28x%2Bsomenumber%29%5E2: %28x%2Bsomenumber%29%5E2+=+x%5E2%2B2%2Asomenumber%2Ax+%2B+somenumber%5E2. Since the coefficient in our equation 1x%5E2%2Bhighlight_red%28+-14%29+%2A+x%2B-16=0 that goes in front of x is -14, we know that -14=2*somenumber, or somenumber+=+-14%2F2. So, we know that our equation can be rewritten as %28x%2B-14%2F2%29%5E2+%2B+othernumber, and we do not yet know the other number.
We are almost there. Finding the other number is simply a matter of not making too many mistakes. We need to find 'other number' such that %28x%2B-14%2F2%29%5E2+%2B+othernumber is equivalent to our original equation 1x%5E2%2B-14x%2Bhighlight_green%28+-16+%29=0.


The highlighted red part must be equal to -16 (highlighted green part).

-14%5E2%2F4+%2B+othernumber+=+-16, or othernumber+=+-16--14%5E2%2F4+=+-65.
So, the equation converts to %28x%2B-14%2F2%29%5E2+%2B+-65+=+0, or %28x%2B-14%2F2%29%5E2+=+65.

Our equation converted to a square %28x%2B-14%2F2%29%5E2, equated to a number (65).

Since the right part 65 is greater than zero, there are two solutions:

system%28+%28x%2B-14%2F2%29+=+%2Bsqrt%28+65+%29%2C+%28x%2B-14%2F2%29+=+-sqrt%28+65+%29+%29
, or

system%28+%28x%2B-14%2F2%29+=+8.06225774829855%2C+%28x%2B-14%2F2%29+=+-8.06225774829855+%29
system%28+x%2B-14%2F2+=+8.06225774829855%2C+x%2B-14%2F2+=+-8.06225774829855+%29
system%28+x+=+8.06225774829855--14%2F2%2C+x+=+-8.06225774829855--14%2F2+%29

system%28+x+=+15.0622577482985%2C+x+=+-1.06225774829855+%29
Answer: x=15.0622577482985, -1.06225774829855.