SOLUTION: Each dimension of a cube has been increased to twice its original size. If the new cube has a volume of 64,000 cubic centimeters, what is the area of one face of the original cube?

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Question 551342: Each dimension of a cube has been increased to twice its original size. If the new cube has a volume of 64,000 cubic centimeters, what is the area of one face of the original cube?

Found 2 solutions by Alan3354, Earlsdon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Each dimension of a cube has been increased to twice its original size. If the new cube has a volume of 64,000 cubic centimeters, what is the area of one face of the original cube?
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%282s%29%5E3+=+64000
Find 2s
Then find s
then one face area = s^2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Original volume of cube with side = xcm:
V%5B1%5D+=+x%5E3cc.
New volume of cube with side = 2x:
V%5B2%5D+=+%282x%29%5E3 and V = 64,000cc.
64000+=+8x%5E3
x%5E3+=+8000 so...
x+=+20cm.
Area of one face of original cube is:
A+=+x%5E2 x = 20
A+=+400sq.cm.