SOLUTION: what is the solution of the following system of equations: x^2-y=4 4x^2+y^2=12

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Question 551341: what is the solution of the following system of equations:
x^2-y=4
4x^2+y^2=12
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-y=4 --> x^2 = y+4
4x^2+y^2=12
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Sub for x^2 in eqn 2
4(y+4) + y^2 = 12
y^2 + 4y + 4 = 0
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y = -2, -2
Sub for y, find x