SOLUTION: I do not understand how the book came up with this answer here is the two equations they are similar however they have different numbers. #(1) 3/(2x+1)-1/x = 2x/x(2x+1) this

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Question 5513: I do not understand how the book came up with this answer
here is the two equations they are similar however they have different numbers.
#(1) 3/(2x+1)-1/x = 2x/x(2x+1)
this is what I am doing
I am multilplying each side by the lcd which is [x(2x+1)]. I understand that there is some canceling out that's why the rightside of the equation is 2x, but how did they get the ans. 3x-(2x+1) for the leftside of the equation. what happens to the 1/X? I can't see how this answer came to be. Please help me. :)
Mrs. Shavette Wiggins
Found 2 solutions by guapa, rapaljer:
Answer by guapa(62) (Show Source):
You can put this solution on YOUR website!
You already found the LCD. Now you have to change each fraction to an equivalent fraction that has the LCD as its denominator. All you do to the denominator to change it to the LCD you also have to do to the numerator.
LCD: x(2x+1)
3/(2x+1)*x/x -1/x*(2x+1)/(2x+1)= 2x/x(2x+1) The equation on the right site already has the LCD in the denominator.It doesn't change.Now, by multiplying an equation by the LCD you clear the equation of all fractions. Thus
3x - (2x+1)= 2x
I hope this helps

Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website!
I'm not sure exactly what you did, but this is the way it looked for me:

It should look like this, when you multiply both sides by the LCD:

Which boils down to this when you clear all the fractions:

Check to make sure none of the denoninators are zero, and it looks okay. It does check if you substitute x= -1 for x.

R^2 at SCC