SOLUTION: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange and each apple. Can u please help me solve this??!
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-> SOLUTION: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange and each apple. Can u please help me solve this??!
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Question 551078: The cost of 12 oranges and 7 apples is $5.36. Eight oranges and 5 apples cost $3.68. Find the cost of each orange and each apple. Can u please help me solve this??! Answer by oberobic(2304) (Show Source):
You can put this solution on YOUR website! x = price of oranges
y = price of apples
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12x + 7y = $5.36 = 536 cents
8x + 5y = $3.68 = 368 cents
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Multiply the first equation by 5, the second by 7, and then subtract to eliminate the 'y' factor.
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60x + 35y = 2680
56x + 35y = 2576
----------------- subtract
4x = 104
x = 26 cents per orange
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Substitute x=26 into the first equation to find 'y'.
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12*26 +7y = 536
312 +7y = 536
7y = 536-312 = 224
y = 32 cents per apple
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Check these values using the other equation.
8*26 = 208 cents
5*32 = 160 cents
208+160 = 368 cents
Correct.
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Answer: Oranges cost 26 cents each; apples cost 32 cents each.
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Done.
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