SOLUTION: Can someone help me on this problem. I have gotten two different results and not sure which was is right. The length of a rectangle is 2 cm more than twice its width. f the

Algebra ->  Expressions -> SOLUTION: Can someone help me on this problem. I have gotten two different results and not sure which was is right. The length of a rectangle is 2 cm more than twice its width. f the       Log On


   

Question 55097: Can someone help me on this problem. I have gotten two different results and not sure which was is right.
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Thanks,
Sher
Found 3 solutions by rchill, funmath, anjulasahay:
Answer by rchill(405) About Me  (Show Source):
You can put this solution on YOUR website!
Let w represent the width, then (2w+2) is the length ("2 more than twice its width"). Because a rectangle's perimeter is 2(l+w), your rectangle's perimeter becomes 2%28%282w%2B2%29%2Bw%29=52. Expanding the equation gives us 2%283w%2B2%29=52 which further expands to 6w%2B4=52. Solving for w gives us w=8, which means the length is 2%2A8%2B2 which is 18. To prove that the rectangle is 8 by 18, it's perimeter should be 52: 8+8+18+18=52. Yeah!

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Hi Sher,
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Let width (W)=x
Then the length (L)=2x+2
The Perimeter (P)=52 cm
The formula for the perimeter of a rectangle is:
highlight%28P=2W%2B2L%29
52=2(x)+2(2x+2)
52=2x+2(2x)+2(2)
52=2x+4x+4
52=6x+4
52-4=6x+4-4
48=6x
48%2F6=6x%2F6
8=x
The width:x=8 cm
The Length: 2x+2=2(8)+2=16+2=18 cm
:
Check:
highlight%28P=2W%2B2L%29
52=2(8)+2(18)
52=16+36
52=52 Looks like we're right!!!
Happy Calculating, Sher!!!
funmath

Answer by anjulasahay(30) About Me  (Show Source):
You can put this solution on YOUR website!
Can someone help me on this problem. I have gotten two different results and not sure which was is right.
The length of a rectangle is 2 cm more than twice its width. f the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle
ans:
let length of the rectangle = l
width of the rectangle = w
hence according to the question ,

l = 2+2*w ----I
and perimeter of rectangle = 2(l+w)
= 2((2+2w)+w) (putting l from I)
=2(2+3w)=52
or 2+3w = 21
or 3w=19
or w = 19/3
hence l = 2+2*19/3 = 44/3