SOLUTION: Expanded form of log8 (a(b-2)^5)/(6c^2)
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Question 550957
:
Expanded form of log8 (a(b-2)^5)/(6c^2)
Answer by
stanbon(75887)
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Expanded form of log8 [(a(b-2)^5)/(6c^2)]
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= log8[a(b-2)^5] - log8[6c^2]
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= log8(a) + 5log8(b-2) - log8(6) - 2log8(c)
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Cheers,
Stan H.
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