SOLUTION: Andrew factored the expression as -12x^3 - 28x^2 - 36x as -4x(3x^2 - 7x + 9).
But when Melissa applied the distributive law and multiplied out -4x(3x^2 - 7x + 9), she got -12x^3
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Andrew factored the expression as -12x^3 - 28x^2 - 36x as -4x(3x^2 - 7x + 9).
But when Melissa applied the distributive law and multiplied out -4x(3x^2 - 7x + 9), she got -12x^3
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Question 550940: Andrew factored the expression as -12x^3 - 28x^2 - 36x as -4x(3x^2 - 7x + 9).
But when Melissa applied the distributive law and multiplied out -4x(3x^2 - 7x + 9), she got -12x^3 + 28x^2 - 36x; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. Answer by ankor@dixie-net.com(22740) (Show Source):
