SOLUTION: The tens digit of a certain two digit number is 1 more than 3 times the units digit. The original number is 9 less than 3 times the number formed by interchanging the digits. Find

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Question 550867: The tens digit of a certain two digit number is 1 more than 3 times the units digit. The original number is 9 less than 3 times the number formed by interchanging the digits. Find the original number. Please help me answer this!
Found 2 solutions by lwsshak3, josmiceli:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The tens digit of a certain two digit number is 1 more than 3 times the units digit. The original number is 9 less than 3 times the number formed by interchanging the digits. Find the original number.
**
let u=unit's digit
let t=ten's digit=3u+1
..
original number: 10t+u=10(3u+1)=30u+10
interchanged number: 10u+t=10u+3u+1=13u+1
..
30u+10=3(13u+1)-9=39u+3-9=39u-6
9u=16
u=2
t=3u+1=7
original number=72

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = tens digit
Let +b+ = units digit
given:
(1) +a+=+3b+%2B+1+
(2) +10a+%2B+b+=+3%2A%28+10b+%2B+a+%29+-+9+
---------------------------
(2) +10a+%2B+b+=+30b+%2B+3a+-+9+
(2) +7a+-+29b+=+-9+
Substitute (1) into (2)
(2) +7%2A%28+3b+%2B+1+%29+-+29b+=+-9+
(2) +21b+%2B+7+-+29b+=+-9+
(2) +-8b+=+-2+
(2) +b+=+1%2F4+
Either I made a mistake, or this is
impossible to solve. Did you copy it right?