SOLUTION: Can someone help me on this problem?
The length of a rectangle is 2 cm. more than twice the width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rect
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The length of a rectangle is 2 cm. more than twice the width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rect
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Question 55085: Can someone help me on this problem?
The length of a rectangle is 2 cm. more than twice the width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.
Thanks,
sher Answer by mathchemprofessor(65) (Show Source):
You can put this solution on YOUR website! Let the width be w cm. So, the length is (2w+2)cm
Perimeter=2( length+ width)=2(2w+2+w)=52
2w+2+w=26
3w+2=26
3w=24
w=8
width=8cm
length=2w+2=16+2=18cm
