SOLUTION: I find this question to be very confusing. Can someone please help with it?
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Show all work. A disc jockey has 10 songs to play. Four are slow songs, and six are fast s
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-> SOLUTION: I find this question to be very confusing. Can someone please help with it?
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Show all work. A disc jockey has 10 songs to play. Four are slow songs, and six are fast s
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Question 550762: I find this question to be very confusing. Can someone please help with it?
Thank you
Show all work. A disc jockey has 10 songs to play. Four are slow songs, and six are fast songs. Each song is to be played only once. In how many ways can the disc jockey play the 10 songs if
The songs can be played in any order.
The first song must be a slow song and the last song must be a slow song.
The first two songs must be fast songs.
In the first case, you simply have 10 different songs and the fact that some are slow and some are fast has no bearing on the outcome. There are 10 ways to pick the first song, then for each of those 10 ways there are 9 ways to pick the second song...etc. Altogether, .
In the second situation, there are 4 ways to choose the first song times 3 ways to choose the last song. That leaves 2 slow songs and 6 fast songs to spread across the other 8 positions: . Altogether
Figure the third one the same way.
John
My calculator said it, I believe it, that settles it
