SOLUTION: Prove that, log(n) >= k.log(2) (Where n >= 2 and "k" denote the number of distinct prime divisors of n).
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-> SOLUTION: Prove that, log(n) >= k.log(2) (Where n >= 2 and "k" denote the number of distinct prime divisors of n).
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Question 550585
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Prove that, log(n) >= k.log(2) (Where n >= 2 and "k" denote the number of distinct prime divisors of n).
Answer by
richard1234(7193)
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We have
This is true because if we let
, then we have
, and since each prime is greater than or equal to 2, this inequality holds.