SOLUTION: How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 550577: How many liters of 20% alcohol solution should be added to 40 liters of a 50% alcohol solution to make a 30% solution?
Found 2 solutions by josmiceli, mathstutor494:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = liters of 20% solution needed
given:
+.5%2A40+=+20+ liters of alcohol in 50% solution
+.2x+ liters of alcohol in 20% solution
-------------
+%28+20+%2B+.2x+%29+%2F+%28+40+%2B+x+%29+=+.3+
+20+%2B+.2x+=+.3%2A%28+40+%2B+x+%29+
+20+%2B+.2x+=+12+%2B+.3x+
+.1x+=+20+-+12+
+.1x+=+8+
+x+=+80+
80 liters of 20% solution are needed
check:
+%28+20+%2B+.2x+%29+%2F+%28+40+%2B+x+%29+=+.3+
+%28+20+%2B+.2%2A80+%29+%2F+%28+40+%2B+80+%29+=+.3+
+%28+20+%2B+16+%29+%2F+120+=+.3+
+36+%2F+120+=+.3+
+36+=+.3%2A120+
+36+=+36+
OK



Answer by mathstutor494(120) About Me  (Show Source):
You can put this solution on YOUR website!
Let quantity of 20% alcohol solution be added : x liters
Eqn for altered solution ....
> x*20% + 40 * 50% = (x+40) * 30%
> x*0.2 + 40*0.5 = (x+40)*0.3 ..(converting percentages into decimal)

> 0.2x + 20 = 0.3x + 12
> 20-12 = 0.3x - 0.2x (Rearranging similar terms)
> 8 = 0.1 x
Hence x = 8/0.1
Ans 80 Litres