SOLUTION: In a train yard, there are 12 flatcars, 10 tanker cars, 15 boxcars, and 5 livestock cars. A. If the cars must be connected according to their final destination, how many

Algebra ->  Probability-and-statistics -> SOLUTION: In a train yard, there are 12 flatcars, 10 tanker cars, 15 boxcars, and 5 livestock cars. A. If the cars must be connected according to their final destination, how many       Log On


   

Question 550576: In a train yard, there are 12 flatcars, 10 tanker cars, 15 boxcars, and 5 livestock cars.
A. If the cars must be connected according to their final destination, how many ways can they be arranged.
B. How many ways can the train be made up if it is to have 30 cars? Is this a combination or permutation? C. How many trains can be formed with 3 livestock cars, 6 flatcars, 6 tanker cars, and 5 boxcars.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a train yard, there are 12 flatcars, 10 tanker cars, 15 boxcars, and 5 livestock cars.
A. If the cars must be connected according to their final destination, how many ways can they be arranged.
Ans: 42!
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B. How many ways can the train be made up if it is to have 30 cars? Is this a combination or permutation?
Ans: Combinations 42C30 = 42!/(12!*30!)
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C. How many trains can be formed with 3 livestock cars, 6 flatcars, 6 tanker cars, and 5 boxcars.
Pick 3 livestock: 5C3
Pick 6 flatcars: 12C6
Pick 6 tankar cars:10C6
Pick 5 boxcars: 15C5
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Ans: Product of the numbers above.
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Cheers,
Stan H.
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