SOLUTION: Two hunters H1 and H2 shoot at a wolf. 0.34 is the probability that H1 will kill a wolf by one shot and 0.51 is the probability that H2 will kill a wolf by one shot, 2 is the n
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-> SOLUTION: Two hunters H1 and H2 shoot at a wolf. 0.34 is the probability that H1 will kill a wolf by one shot and 0.51 is the probability that H2 will kill a wolf by one shot, 2 is the n
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Question 550527: Two hunters H1 and H2 shoot at a wolf. 0.34 is the probability that H1 will kill a wolf by one shot and 0.51 is the probability that H2 will kill a wolf by one shot, 2 is the number of shots performed by H1 and 3 is the number of shots performed by H2. Find the probability that after 5 shots the wolf is not killed. Answer by TutorDelphia(193) (Show Source):
You can put this solution on YOUR website! If .34 is the probability H1 will kill it, than 1-.34=.66 is the probability he won't. Same goes for H2 which will be .49
So we have
.66*.66*.66 *.49*.49=.069
Poor woof.
