SOLUTION: Factor by grouping, if possible, and check 8a3 − 2a2 + 12a − 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) (2a^2 + 3) + (4a - 1) The instructor says this

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: Factor by grouping, if possible, and check 8a3 − 2a2 + 12a − 3 (8a^3 - 2a^2) + (12a - 3) 2a^2(4a - 1) + 3(4a - 1) (2a^2 + 3) + (4a - 1) The instructor says this       Log On


   

Question 550397: Factor by grouping, if possible, and check
8a3 − 2a2 + 12a − 3
(8a^3 - 2a^2) + (12a - 3)
2a^2(4a - 1) + 3(4a - 1)
(2a^2 + 3) + (4a - 1)
The instructor says this is wrong, but I don't understand why. All I was told is to check the last line. Help plz!!
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Factor by grouping, if possible, and check
8a3 − 2a2 + 12a − 3
(8a^3 - 2a^2) + (12a - 3)
2a^2(4a - 1) + 3(4a - 1)
Factor out the (4a-1) to get:
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(4a - 1)(2a^2+3)
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Cheers,
Stan H.
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