SOLUTION: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination?
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-> SOLUTION: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination?
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Question 550285: The length of a rectangle is 4 times the width. The perimeter is 50 cm. Find the length and width. Can you show me how to do this, maybe by elimination? Answer by TutorDelphia(193) (Show Source):
You can put this solution on YOUR website! l=4w
2l+2w=50 (this is from the perimeter formula 2l+2w=p
You mentioned you wanted to do this using the elimination method. Let's get both equations in good form for that.
l=4w
subtract 4w from both sides
l-4w=0
2l+2w=50
divide both sides by 2
l+w=25
minus
l-4w=0
5w=25 (minus -4w gives us +4w)
w=5
l=20
