SOLUTION: What is the minimum value of 2x^2-8x+7 ?

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Question 550114: What is the minimum value of 2x^2-8x+7 ?
Answer by prateekagrawal(56) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 -8x+7
=2(x^2 -4x) +7
= 2(x^2 -4x +4 -4) +7
= 2(x^2 -4x +4) -8+7
= 2(x-2)^2 -1
when x=2
.
its 2(0)^2 -1
= -1
so, -1 is the minimum value of this.