SOLUTION: Find the real roots of f(x)=x^4-16
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Question 549818
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Find the real roots of f(x)=x^4-16
Answer by
jim_thompson5910(35256)
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f(x) = x^4-16
0 = x^4-16
x^4-16 = 0
(x^2-4)(x^2+4) = 0
(x-2)(x+2)(x^2+4) = 0
x-2=0, x+2=0, or x^2+4=0
x=2, x=-2, x=2i, or x=-2i
So the real roots are 2 and -2