SOLUTION: h=-16t^2-32t+320 gives the height of a ball thrown downward from the top of a 320 foot building with an initial velocity of 32 feet per second. Find the time in seconds that it tak

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Question 549773: h=-16t^2-32t+320 gives the height of a ball thrown downward from the top of a 320 foot building with an initial velocity of 32 feet per second. Find the time in seconds that it takes for the ball to reach a height of 48 feet.
Answer by Alan3354(69443) About Me  (Show Source):
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h=-16t^2-32t+320 gives the height of a ball thrown downward from the top of a 320 foot building with an initial velocity of 32 feet per second. Find the time in seconds that it takes for the ball to reach a height of 48 feet.
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Set h=-16t^2-32t+320 = 48
-16t%5E2-32t%2B+272+=+0
-t%5E2+-+2t+%2B+17+=+0
Solve for t