SOLUTION: an experiment consists of rolling a fair die three times, what is the probability of getting a number divisable by 3 on all three rolls?

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Question 549704: an experiment consists of rolling a fair die three times, what is the probability of getting a number divisable by 3 on all three rolls?
Answer by stanbon(75887) About Me  (Show Source):
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an experiment consists of rolling a fair die three times, what is the probability of getting a number divisable by 3 on all three rolls?
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Binomial Problem with n = 3 and p(divible by 3) = 2/6 = 1/3
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P(all three divisible by 3) = (1/3)^3 = 1/27
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Cheers,
Stan H.