SOLUTION: What is the solution for the compound inequality 3x + 8 < 2 or x + 12 > 2 - x ?

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Question 549347: What is the solution for the compound inequality 3x + 8 < 2 or x + 12 > 2 - x ?

Found 2 solutions by mathie123, karaoz:
Answer by mathie123(224) About Me  (Show Source):
You can put this solution on YOUR website!
3x+%2B+8+%3C+2 (1)
x+%2B+12+%3E+2+-+x (2)
Looking at (1) we can see that:
3x+%3C+2-8
3x+%3C-6
3x%2F3+%3C-6%2F3
x+%3C-2

Looking at (2) we can see that
x+%2B+12%2Bx+%3E+2+-+x%2Bx
2x+%2B+12+%3E2
2x+%3E2-12
2x+%3E-10
x+%3E-10%2F2
x+%3E-5


So to satisfy both (1) and (2) we must have -5%3Cx%3C-2

Answer by karaoz(32) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
(1) 3x + 8 < 2
(2) x + 12 > 2 - x

Simplify both inequalities:
take away 8 from both sides of (1) and add x-12 to both sides of (2).
(1) 3x < -6
(2) 2x > -10

Simplify further:
divide (1) by 3 and divide (2) by 2
(1) x < -2
(2) x > -5

Assuming compound inequality means that both inequalities have to be satisfied at the same time then the last set of two inequalities represent solution to the problem. This solution can be also expressed in the following form:
-5 < x < -2.

Translated into English, the solution is:
x has to be larger than -5 and smaller than -2.