SOLUTION: One angle of a triangle has a measure of 70 degrees. The other two angles have degree measures in a ratio of 5 to 6. What is the sum of the measures, in degrees, of the two largest

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Question 54924: One angle of a triangle has a measure of 70 degrees. The other two angles have degree measures in a ratio of 5 to 6. What is the sum of the measures, in degrees, of the two largest angles?
I first tried 50 +60=110+70=180. Then I realized that 180 is the sum of all of the angles in a triangle, so it couldn't be right. Thanks if you can help!
Found 2 solutions by Earlsdon, venugopalramana:
Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website!
You have the right answer.
The sum of the three angles is 180, so the sum of the two unknown angles is 180-70 = 110 degrees.
Call these angles a and b, so a+b = 110 and a/b = 5/6, so you can solve for a and b.
and:
Solve this for a:
and substitute for a in the first equation.
Simplify by multiplying through by 6.

and = 50
The sum of the two largest angles is:
70 + 60 = 130 degrees.

Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website!
One angle of a triangle has a measure of 70 degrees. The other two angles have degree measures in a ratio of 5 to 6. What is the sum of the measures, in degrees, of the two largest angles?
I first tried 50 +60=110+70=180.
ONE ANGLE =70
HENCE SUM OF OTHER 2 ANGLES = 180-70=110...YOU ARE CORRECT!WHY DOUBT?
SINCE ANGLES ARE IN 5:6 RATIO...TAKE THEM AS 5X,6X
5X+6X=11X=110...HENCE X=110/11=10
SO THE 2 ANGLES ARE 50,60..
Then I realized that 180 is the sum of all of the angles in a triangle, so it couldn't be right.
WHY IT IS RIGHT ..SUM OF 3 ANGLES 50,60,70 IS 180
Thanks if you can help!