SOLUTION: Can someone help me on this?
Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at
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Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at
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Question 54912: Can someone help me on this?
Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil?
Thanks, Adriana Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! distance = (rate)(time) [Use the formula for distance while traveling (d=rt)]
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Ching's distance=rt=(50mph)(unknown time)
Phil's distance=rt= 60mph)(unknown time - 1hour)
Ching's distance (rt) + Phil's distance(rt) = 380
So, 50t+60(t-1)=380
50t+60t-60=380
110t=60+380
110t=440
t=4 hours
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Check by plugging all of the variables back into the original equation:
50t+60(t-1)=380
50(4)+60(4-1)=380
200+180=380
380=380 [Checks out]
