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Question 549103: I need help on a word problem.
A 20 meter ladder and a 15 meter ladder were leaned against a building. The bottom of the longer ladder was 7 meters farther from the building than the bottomof the shorter ladder, but both ladders reached the same distance up the building. Find the distance the ladders reached up the building.
I don't even remember how to begin to do this.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! I need help on a word problem.
A 20 meter ladder and a 15 meter ladder were leaned against a building. The bottom of the longer ladder was 7 meters farther from the building than the bottomof the shorter ladder, but both ladders reached the same distance up the building. Find the distance the ladders reached up the building.
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Draw the two right triangle.
longer hypotenuse = 20 meters; shorter hypotenuse = 15 meters
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longer base = x+7 ; shorter base = x
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height for both is the same
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20^2 = h^2 + (x+7)^2
15^2 = h^2 + x^2
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Subtract to solve for "x":
175 = (x^2+14x+49) - x^2
14x+48 = 175
14x = 127
x = 9.07 meters
x+7 = 16.07 meters
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Cheers,
Stan H.
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