SOLUTION: by elimination x – 3y + 4z = –9 2x + y + 3z = 6 x – 4y + 3z = –9
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-> SOLUTION: by elimination x – 3y + 4z = –9 2x + y + 3z = 6 x – 4y + 3z = –9
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Question 549049
:
by elimination
x – 3y + 4z = –9
2x + y + 3z = 6
x – 4y + 3z = –9
Answer by
Alan3354(69443)
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Subtract Eqn 3 from Eqn 1. --> eqn in y & z
Subtract 2 times Eqn 3 from Eqn 2. --> another eqn in y & z
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2 eqns in y & z
Can you finish it?