4x² - 3xy = 18
We write it in the form of the general conic:
Ax² + Bxy + Cy² + Dx + Ey + F = 0
4x² - 3xy + 0y² + 0x + 0y - 18 = 0
So A=4, B=-3, C=0, D=0, E=0, F=-18
To find the angle to rotate the graph, we use:
tan(2Ɵ) =
tan(2Ɵ) =
tan(2Ɵ) =
Use the identity for tan(2Ɵ)
tan(2Ɵ) =
=
8tanƟ = -3(1 - tan²Ɵ)
8tanƟ = -3 + 3tan²Ɵ
-3tan²Ɵ + 8tanƟ + 3 = 0
3tan²Ɵ - 8tanƟ - 3 = 0
That factors:
(tanƟ - 3)(3tanƟ + 1) = 0
tanƟ - 3 = 0 3tanƟ + 1 = 0
tanƟ = 3 tanƟ =
Ɵ = arctan(3) Ɵ = arctan(
)
Ɵ = 71.56505118° Ɵ = 161.5650512° or 341.5650512°
or 251.5650512°
Either of those angles will eliminate the xy term when rotated through
them. We choose Ɵ = arctan(3) = 71.56505118°.
We draw the triangle:
and use the Pythagorean theorem to find the hypotenuse:
Next we substitute
x = x'cosƟ-y'sinƟ = x'
-y'
=
(x' - 3y')
y = x'sinƟ+y'cosƟ = x'
+y'
=
(3x' + y')
in
4x² - 3xy = 18
4(
(x' - 3y'))² - 3(
(x' - 3y'))(
(3x' + y')) = 18
4(
)²(x' - 3y')² - 3(
)²(x' - 3y')(3x' + y') = 18
4(
)(x' - 3y')² - 3(
)(x' - 3y')(3x' + y') = 18
Multiply through by 10
4(x' - 3y')² - 3(x' - 3y')(3x' + y') = 180
4(x'² - 6x'y' + 9y'²) - 3(3x'² - 8x'y' - 3y'²) = 180
4x'² - 24x'y' + 36y'² - 9x'² + 24x'y' + 9y'² = 180
-5x'² + 45y'² = 180
Divide through by 180 to get 1 on the right side
x'² +
y'² =
+
= 1
Write the positive term first:
-
= 1
This is a hyperbola of the form
-
= 1
rotated through an angle of Ɵ = arctan(3) = 71.56505118°.
a = 2 and b = 6
We will draw the x' and y' axes in green:
We draw in the defining rectangle, 6 units out the x' axis in
both directions, and 2 units out the y' axis in both directions.
We draw in the asymptotes as the extended diagonals of the
defining rectangle, one of which turns out to be the y-axis:
And we sketch in the hyperbola:
Edwin