SOLUTION: A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags of 2% and 8% saline solutions. How many liters of each of these solutions should be mixed to
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Question 548946: A dehydrated patient needs a 6.8% saline IV. Unfortunately, the hospital only has bags of 2% and 8% saline solutions. How many liters of each of these solutions should be mixed together to yield 2 liters of the desired concentration? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Saline I 2 ----------------x L
Saline II 8 ------ 2-x L
Mixture 6.80% ---------------- 2
2x+8(2-x)=6.8*2
2x+16-8x=13.6
2x-8x= 13.6-16
-6x=-2.4
/ -6
x=0.4 L 2.00% Saline I
1.6 L 8.00% Saline II
