SOLUTION: write an equation in slope intercept form for the line that satisfies each set of conditions. passes through (4,6) parallel to the graph of Y=2/3x+5

Algebra ->  Coordinate-system -> SOLUTION: write an equation in slope intercept form for the line that satisfies each set of conditions. passes through (4,6) parallel to the graph of Y=2/3x+5      Log On


   

Question 54879: write an equation in slope intercept form for the line that satisfies each set of conditions.
passes through (4,6) parallel to the graph of Y=2/3x+5
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
write an equation in slope intercept form for the line that satisfies each set of conditions.
passes through (4,6) parallel to the graph of Y=2/3x+5
The line you're given is in slope intercept form: highlight%28y=mx%2Bb%29 where m=slope and (0,b)=y-intercept.
y=highlight%282%2F3%29x%2B5 it's slope m=2/3.
Parallel lines have the same slope, so you need and equation of a line with a slope m=2/3 going through (x1,y1)=(4,6)
When you have a point and a slope and need the equation of a line you use the point slope formula: highlight%28y-y1=m%28x-x1%29%29, where m=slope and (x1,y1) is the point you're going through.
your m=2/3 and (x1,y1)=(4,6)
y-6=%282%2F3%29%28x-4%29
3%28y-6%29=3%282%2F3%29%28x-4%29
3y-18=%286%2F3%29%28x-4%29
3y-18=2%28x-4%29
3y-18=2x-8
3y-18%2B18=2x-8%2B18
3y=2x%2B10
3y%2F3=2x%2F3%2B10%2F3
highlight%28y=%282%2F3%29x%2B10%2F3%29
Happy Calculating!!!