SOLUTION: how do you evaluate this function? h(x)=5/2x+x^2 find h(-3/10)

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Question 548761: how do you evaluate this function? h(x)=5/2x+x^2 find h(-3/10)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
h(x)=5/2x+x^2


h(-3/10)=(5/2)(-3/10)+(-3/10)^2


h(-3/10)=(5/2)(-3/10)+9/100


h(-3/10)=-15/20+9/100


h(-3/10)=-3/4+9/100


h(-3/10)=-75/100+9/100


h(-3/10)=-66/100


h(-3/10)=-33/50


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