SOLUTION: I have a problem that I do not know how to do, the question is 25y^2= 289, My teacher says that since it is raised to the 2nd power that I need two answers.

Algebra ->  Square-cubic-other-roots -> SOLUTION: I have a problem that I do not know how to do, the question is 25y^2= 289, My teacher says that since it is raised to the 2nd power that I need two answers.      Log On


   

Question 548746: I have a problem that I do not know how to do, the question is 25y^2= 289, My teacher says that since it is raised to the 2nd power that I need two answers.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
25y%5E2=289 Start with the given equation.


y%5E2=%28289%29%2F%2825%29 Divide both sides by 25.


y=%22%22%2B-sqrt%28289%2F25%29 Take the square root of both sides.


y=sqrt%28289%2F25%29 or y=-sqrt%28289%2F25%29 Break up the "plus/minus" to form two equations.


y=17%2F5 or y=-17%2F5 Take the square root of 289%2F25 to get 17%2F5.


--------------------------------------


Answer:


So the solutions are y=17%2F5 or y=-17%2F5.


If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim