SOLUTION: 15. A can of soda at 90° F. is placed in a refrigerator that maintains a constant temperature of 36°
F. The temperature T of the soda t minutes after it is placed in the refrigera
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-> SOLUTION: 15. A can of soda at 90° F. is placed in a refrigerator that maintains a constant temperature of 36°
F. The temperature T of the soda t minutes after it is placed in the refrigera
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Question 548631: 15. A can of soda at 90° F. is placed in a refrigerator that maintains a constant temperature of 36°
F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by
T(t) = 36 + 54 e^(– 0.058) t
Find the temperature of the soda 12 minutes after it is placed in the refrigerator. (Round to the nearest degree.) Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! T(t) = 36 + 54 e^(– 0.058) t
I believe you meant the 't' to be part of the exponent:
T(t) = 36 + 54 e^(– 0.058t)
.
substitute 12 for t and solve:
T(12) = 36 + 54 e^(– 0.058*12)
T(12) = 36 + 54 e^(– 0.696)
T(12) = 36 + 54(.4986)
T(12) = 36 + 29.9
T(12) = 62.9
rounding:
T(12) = 63 degrees
