SOLUTION: What is ordered pair of real numbers (x, y) for which 16^x – 16^y = 192 and 4^x – 4^y = 8

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Question 548599: What is ordered pair of real numbers (x, y) for which 16^x – 16^y = 192 and 4^x – 4^y = 8
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is ordered pair of real numbers (x, y) for which
16^x – 16^y = 192
and 4^x – 4^y = 8
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Divide the 1st by the 2nd to get:
4^x+4^y = 24
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Add that to 4^x-4^y = 8 to get:
2*4^x = 32
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4^x = 16
x = 2
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Solve for "y":
4^x+4^y = 24
16 + 4^y = 24
4^y = 8
2^(2y) = 2^3
2y = 3
y = (3/2)
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Solution: (2,3/2)
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Cheers,
Stan H.
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