SOLUTION: A triangle has vertices at coordinates (2,2), (5,6) and (6,2). What is the number of units in the length of the longest side of the triangle?

Algebra ->  Length-and-distance -> SOLUTION: A triangle has vertices at coordinates (2,2), (5,6) and (6,2). What is the number of units in the length of the longest side of the triangle?      Log On


   

Question 548570: A triangle has vertices at coordinates (2,2), (5,6) and (6,2). What is the number of units in the length of the longest side of the triangle?
Answer by asuar010(338) About Me  (Show Source):
You can put this solution on YOUR website!
the distance formula between points is +d=sqrt%28%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%29+
so if we assign (2,2) as A, (5,6) as B and (6,2) as C the length of the sides is as follows AB=5, BC=4.1, and AC=4... so the longest side is AB.