SOLUTION: Divide (24b^3+22b^2+22b+45)/(4b+5)

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Question 548515: Divide (24b^3+22b^2+22b+45)/(4b+5)
Answer by mananth(16946) About Me  (Show Source):
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(24b^3+22b^2+22b+45)/(4b+5)


4b+5)24b^3+22b^2+22b+45(6b^2-2b+8
- 24b^3+30b^2
----------------
-8b^2+22b+45
-8b^2-10b
---------
32b+45
32b+40
----------
5
6b^2-2b+8
remainder = 5